题意：给出英文，翻译成数字形式。

分析：运用sscanf函数将每个数字提取出来，用num[i]存这些数字，数字中有100,1000,1000000是位权，因为如果像普通的比如twenty two的话，只要简单的相加。那么碰到关键词我是这么想的，我建立四个int型变量hsum，tsum，msum和sum。看名字可以看出hsum就是用来存碰到关键词hundred时的和，其他依此类推，sum就存没有关键词的和。首先把他们都置为0，当碰到hundred关键词时，hsum=sum*100，同时把sum置为0。碰到关键词thousand时，tsum=(hsum+sum)*1000，同时把hsum和sum都置为0。msum也一样类推。

wa的原因：1A。

AC代码：

#include<iostream>
#include<cstring>
#include<stdio.h>
using namespace std;
int main(){
	char str[10000];
	char n[10000][100];
	int num[10000];
	while(gets(str)!=NULL){
		if(strcmp(str,"")==0){break;}
		int len=strlen(str);
		int k=1;
		int a[10000];
		memset(a,0,sizeof(a));
		memset(n,0,sizeof(n));
		memset(num,0,sizeof(num));
		a[0]=0;
		for(int i=1;i<len;++i){
			if(str[i]==' '){
				a[k++]=i+1;	
			}	
		}
		for(int i=0;i<k;++i){
			sscanf(str+a[i],"%s",n[i]);
		}
		for(int i=0;i<k;++i){
			if(strcmp(n[i],"negative")==0)num[i]=-1;
			else if(strcmp(n[i],"zero")==0)num[i]=0;
			else if(strcmp(n[i],"one")==0)num[i]=1;
			else if(strcmp(n[i],"two")==0)num[i]=2;
			else if(strcmp(n[i],"three")==0)num[i]=3;
			else if(strcmp(n[i],"four")==0)num[i]=4;
			else if(strcmp(n[i],"five")==0)num[i]=5;
			else if(strcmp(n[i],"six")==0)num[i]=6;
			else if(strcmp(n[i],"seven")==0)num[i]=7;
			else if(strcmp(n[i],"eight")==0)num[i]=8;
			else if(strcmp(n[i],"nine")==0)num[i]=9;
			else if(strcmp(n[i],"ten")==0)num[i]=10;
			else if(strcmp(n[i],"eleven")==0)num[i]=11;
			else if(strcmp(n[i],"twelve")==0)num[i]=12;
			else if(strcmp(n[i],"thirteen")==0)num[i]=13;
			else if(strcmp(n[i],"fourteen")==0)num[i]=14;
			else if(strcmp(n[i],"fifteen")==0)num[i]=15;
			else if(strcmp(n[i],"sixteen")==0)num[i]=16;
			else if(strcmp(n[i],"seventeen")==0)num[i]=17;
			else if(strcmp(n[i],"eighteen")==0)num[i]=18;
			else if(strcmp(n[i],"nineteen")==0)num[i]=19;
			else if(strcmp(n[i],"twenty")==0)num[i]=20;
			else if(strcmp(n[i],"thirty")==0)num[i]=30;
			else if(strcmp(n[i],"forty")==0)num[i]=40;
			else if(strcmp(n[i],"fifty")==0)num[i]=50;
			else if(strcmp(n[i],"sixty")==0)num[i]=60;
			else if(strcmp(n[i],"seventy")==0)num[i]=70;
			else if(strcmp(n[i],"eighty")==0)num[i]=80;
			else if(strcmp(n[i],"ninety")==0)num[i]=90;
			else if(strcmp(n[i],"hundred")==0)num[i]=100;
			else if(strcmp(n[i],"thousand")==0)num[i]=1000;
			else if(strcmp(n[i],"million")==0)num[i]=1000000;
	//		cout<<num[i]<<" ";
		}
	//	cout<<endl;
		long long sum=0,msum=0,tsum=0,hsum=0;
		if(num[0]==-1){
			for(int i=1;i<k;++i){
				if(num[i]==100){
					hsum=sum*100;
					sum=0;
				}
                                else if(num[i]==1000){
					tsum=(hsum+sum)*1000;
					hsum=0;
					sum=0;
				}
				else if(num[i]==1000000){
					msum=(tsum+hsum+sum)*1000000;
					tsum=0;
                                       	hsum=0;
                                        sum=0;
                                }
                                else sum+=num[i];

			}	
			cout<<-1*(msum+hsum+tsum+sum)<<endl;
		}
		else {
			for(int i=0;i<k;++i){
				if(num[i]==100){
					hsum=sum*100;	
					sum=0;
				}	
				else if(num[i]==1000){
					tsum=(hsum+sum)*1000;
					hsum=0;
					sum=0;
				}
				else if(num[i]==1000000){
					msum=(tsum+hsum+sum)*1000000;
					tsum=0;
					hsum=0;
					sum=0;
				}
				else sum+=num[i];
			}
			cout<<msum+hsum+tsum+sum<<endl;
		}
	}
	return 0;
}